If we’re treating y & x as constants wouldn’t that mean when getting the derivative they would become zero? I’ve been searching around YT and have really struggled through this for the past couple days, any help would be appreciated.
Tangentially, this makes it tough to approach the next problem as I’m not understanding the intuition here.
Please format your post appropriately. Right now, most of it is one letter/character per line and it’s unclear what exactly you are trying to ask about. Also, make sure to include the link to the Mission/Mission Step you are referring to.
It depends. Consider the function f\colon \mathbb R\rightarrow \mathbb R, a\mapsto 17 (in words, the function defined over the real numbers that is constantly 17). If you differentiate this, then you get the constantly zero function.
Now consider g\colon \mathbb R\rightarrow \mathbb R, a\mapsto 2a. Here the constant (relative to your question) is 2. Do you expect to get the zero function when differentiating g?
Going back to the lesson, replace x^{(i)} and y^{(i)} with some actual numbers, just help think about this. That is, differentiate, for example,
Ohhhh ok, I think I get it. Using the actual numbers presented we get: 2a1 - 3. The 3 ‘disappears’ when differentiating the function and because we’re differentiating with respect to a1, x1 is the only variable left.
Is my understanding correct? And thank you, I was initially frustrated my your explanation but it was deceptively helpful.
