pattern = r"[Pp]ython ([\d.]+)"
Screen Link:
My Code:
pattern =r"[Pp]ython ?([\d.]+)"
What I expected to happen:
I expect this to be correct
What actually happened:
Value of py_versions_freq is not what we expected.
In the “Learn” section, it said that ‘All of these examples have a number after the word “Python,” which indicates a version number. Sometimes a space precedes the number, sometimes it doesn’t.’
Thus, I would expect that we need a question mark after the space to match the cases where there is no space preceding the number?
Thank you!
