Dictionary practice problem 6 (I am stucked)

Q&A DQ Courses
#1 
def remove_rows(dic,row_list):
    new=[]
    column=[]
    for key,value in dic.items():
        column.append(key)
        for k,v in value.items():
            if k not in row_list and k not in new:
                new.append(k)
    final={}
    for col in column:
        for index in new:
            print(dic[col][index])

my task was to create a function that returns a new dictionary without the rows that have their index specified in the row_list /second augment in the function created.

Nb. I don’t understand the clean method used as the answer. hence the reason why I attempted to create my own from scratch. I dislike this method because it doesnt give me a chance to appreciate what is going on behind the scene

For my function created above, I got stuck. I have managed to print out the values associated to the indices not in row_list. but how to relate what I have managed to achieve back to the format {column_name: {index: value}} to create a new dictionary which I could return is were am stucked at.

any help to enable me finish up my code and understand the clean and shorter method used in the solution provided is welcomed

#2

Hi!
I followed the similar logic in my solution, so it´s easy to help you to finish yours.
In you last step, when you iterate over the columns you have to instantiate an empty dictionary which will be a value of your final dicationary and you´ll fill it with keys/values while iterating over the indexes.

final={}
    for col in column:
        final[col] = {}
        for index in new:
            final[col][index] = dic[col][index]

As for the suggested solution, thanks to dictionary comprehension it looks clean and explicit, but sometimes it difficult to understand what´s happening behind when you are just starting.
So, my advice would be, first, to rewrite the solution´s code without dictionary comprehensions, only using for-loop operator but keeping the functions as they are. And if it´s still difficult to comprehend, then substitute calling the remove_keys() function inside the remove_rows() function, the one that returns the desired output.