Help: try except block confusion

[shibalik.sanyal]

Hi
I’m trying to write a display_data function which prints the first 5 rows of a data frame
acc to user input…further prints the next 5 rows acc to user input and continues until the user says no…
How do i deal with the case when the user inputs a string other than yes or no?
should i add a condition for that?
also my code is not handling the exception when user inputs an integer

code:(the if row_data ==“yes” is not inside the first while loop, try and except block is inside)

def display_data(df):
while True:
try:
row_data = str(input(“Would you like to see raw data form the table?(type yes or no):”)).lower()
break
except:
print(“That’s not a valid input…please try again”)

if row_data == "yes":
    print(df.iloc[:5])
    c = 5
    while c < len(df.index):
        
        try:
            row_next_data = str(input("Would you like to see 5 more rows of data?(type yes or no):")).lower()
            if row_next_data == "yes":
                print(df.iloc[c-5:c])
                c += 5
            elif row_next_data == "no":
                break    
            
        except:
            print("That's not a valid input...please try again")

[alvinctk]

How do i deal with the case when the user inputs a string other than yes or no?

All inputs are read as a string.

x = input(“Enter your sentence”) 

Please use triple back ticks ``` to format a code block. See the post below on how to format code block using triple back ticks.

Discourse post - markdown formatting a block of code to improve readability

By formatting a block to show indentation helps in better code readability, and easier to read and faster response from the community if you ever post a question here.

Using triple back ticks to format a block of code

Transform the text from x = 67 for i in range(100): if i < x: print(i) else: print(x+i) by using ``` triple back ticks to format a block of code to show indent ``` x = 67 for i in range(100): if i < x: print(i) else: print(x+i) ``` , and transform the code int…

[shibalik.sanyal]

sorry…this is not a part of any mission…I’ll make sure to include the format for code…
if i change the line of the code to x = int(input(“enter a number:”)) (say i want a number)
then it checks for the input until the user enters a valid integer unlike the str case which i mentioned earlier…why?

[alvinctk]

I’ll make sure to include the format for code…
if i change the line of the code to x = int(input(“enter a number:”)) (say i want a number)

.input returns a string. If you want a int type as your input, you have to cast the string into an int.

while True:
       try:
            x = int(input(“enter a number:”))
            break
       except ValueError:
            print("That's not a valid input...please try again")
       

The try statement works as follows.

• First, the try clause (the statement(s) between the try and except keywords) is executed.
• If no exception occurs, the except clause is skipped and execution of the try statement is finished.
• If an exception occurs during execution of the try clause, the rest of the clause is skipped. Then if its type matches the exception named after the except keyword, the except clause is executed, and then execution continues after the try statement.
• If an exception occurs which does not match the exception named in the except clause, it is passed on to outer try statements; if no handler is found, it is an unhandled exception and execution stops with a message as shown above.

[shibalik.sanyal]

so in the code that I mentioned earlier…
I need to add a seperate condition for the case when the user inputs a string other than yes or no…right?
bcz it does’nt generate any error…

[alvinctk]

You can use the above example to format your code base on your required logic requirements.

[moriturus7]

Yes, you need to further process this condition. But your code already has everything you need for this, you just need to add else,in which you will handle all input cases except yes and no
You will receive the following

if row_data == "yes":
    print(df.iloc[:5])
    c = 5
    while c < len(df.index):
        
        try:
            row_next_data = str(input("Would you like to see 5 more rows of data?(type yes or no):")).lower()
            if row_next_data == "yes":
                print(df.iloc[c-5:c])
                c += 5
            elif row_next_data == "no":
                break    
            else: # other case
               print("That's not a valid input..only 'yes' or 'no'")
        except:
            print("That's not a valid input...please try again")