Please I need held in understanding why laptop1 and laptop 2 are not giving me unique names

Q&A DQ Courses
#1

Screen Link:
https://app.dataquest.io/m/1011/dictionaries-practice-problems/12/laptop-purchase

My Code: 

from csv import reader
openfile=open('laptops.csv')
readfile= reader(openfile)
file=list(readfile)[1:]
price_to_name={}
for f in file:
    name=f[1]
    price= int(f[2])
    if price in price_to_name:
         price_to_name[price].append(name)
    else:
        price_to_name[price]=[name]
price_to_name

laptop1=None
laptop2=None
for price in price_to_name:
    price1= 5000-price
    if price1 in price_to_name and price !=price1:
        
        laptop1=price_to_name[price]
        laptop2=price_to_name[price1]
        
print(price, price1)
print(laptop1,laptop2)

What I expected to happen:
I expected unique laptop names

What actually happened:
Laptop 1 and laptop 2 still gives me none

#2

Given that laptop1 and laptop2 are only reassigned inside an if condition, and given that they remain None, then the code execution must not be entering this condition, that is, price1 in price_to_name and price !=price1 never holds.

Here’s a hint: does your solution capture cases in which laptops have the same price? Specifically, if they cost $2500?

#3

Thanks Bruno, I was trying to figure out a code not involving same price.

I will follow your hint, thanks again