Variables and Data Types

Q&A
#1

My question 1. Store the value 15 in a variable named a_value.
2. Store the result of (25 - 7) * 17 to a variable named a_result.
3. Using the print() command, display the following:

  • The value stored in the a_value variable.
  • The result of adding 12 to the variable a_result.
  • The result of adding a_value to a_result
    my answer
    a_value=15
    a_result= (25-7)*17
    print(a_value)
    print(a_result)
    print(a_value+12)
    print(a_result+a_value)
    Output

  • actual + expected

    15

  • 306

  • 27

  • 318
    321
1 Like
#2

Welcome to the DQ community!

Unfortunately, I’m not sure what your question is exactly or where this exercise comes from…can you please provide a link to the mission? Maybe this link could help make your question more clear.

It looks like the instructions are asking you to print 3 results:

  • a_value
  • a_result + 12
  • a_value + a_result

But it appears you have 4 printed results (based on the output):

  • a_value :white_check_mark:
  • a_result :x:
  • a_value + 12 :x:
  • a_result + 12 :x:

Can you please clarify?

#3

this is 2/12 of exercise
. I entered the data as given above and the answer is also stated above but the system isn’t accepting the result can you give the clue to move forward.

#4

I’m not sure which exercise you’re referring to…can you provide a direct link to the mission please?

#5

I found the mission you’re working on. It can be found here

Here is the solution I came up with and the system accepted it:

a_value=15
a_result=(25 - 7) * 17

print(a_value)
print(12 + a_result)
print(a_value + a_result)

What happens if you submit this?

#6

Hi @zubairulhassan28

I think with what you have given, 12 is being added to a_result but you have added it to a_value instead, kindly recheck and do the changes, and also with the instruction given you should have three output , you shouldn’t print the value contained in the a_result for you to maintain the required output.